[frostfire]

Reaper Sir, thanks for the links. Those are what I've been looking for for years. My google-fu needs tons of tune-ups.

Originally Posted by kgoerz

...we read winds 2/3 the distance to the target.....
...wind effects the Bullet at this point more then any other...
...wind will move the ball in that split second it becomes weightless...
...we read winds where the Bullet reaches it's max trajectory...
...Bullet becomes weightless like the ball...
...At this point the effects of wind overtake the effects of gravity.
...wind speed at your shooting position is of little importance...

ugh...nerd time! I'll be here all night. So I better share the headache. I may have to PM longrange on this when it gets too long and convoluted

1. The tradeoff puzzle. The wind affects the bullet more the further it is from the muzzle as it is losing its kinetic energy/forward momentum. On the other hand, while the effect of wind is small at muzzle, the smallest deviation caused by the wind will propagate over distance.
So the correct answer is at 2/3 the distance ??? Why?

2. Since trajectory is the path a moving object follows through space, what is max trajectory? The end of the path? The point where bullet is weightless? The ball analogy works where force of gravity = upward force (that split second 0 gravity state at max height), but then the bullet will also have to be at the max height and that is 1/2 of the distance, not 2/3 ???

I've almost given up 100% testing scientific reasonings at the range and accepted what the old salts said that lrs is more of an art than science. Indeed, paying attention to basics, being in the "zone" and hard holds give more results that xyz physics, but still...."curiosity kills the cat, but satisfaction brings it back"